Good morning,
I am interested in purchasing a new system but I have question how much KVA I would need to drive a shaker.
This is what I would want:
Stroke = 2"
Pounds of force = 8,000 - 15,000
Sine = 120 - 150g
Random = 80 - 100g RMS
Say I have a shaker with a force of 10,000lbs and 110 lbs between armature, fixture & test item. How would I calculate how much KVA I would need to drive the shaker?
Thank-you
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