anyone want to help with this math problem? September 30 2009 at 6:04 PM Amber (no login ) Anyone want to see if you can determine the missing numbers and a rule (equation) for this x/y chart?
x y
1 8
2 14
3 ?????
????? 24
????? 28
6 ?????
Author Reply Bider Spite (Login Bider ) Re: anyone want to help with this math problem? September 30 2009, 6:25 PM
Amber (no login ) Re: anyone want to help with this math problem? September 30 2009, 6:28 PM
2, 14. I had them spread out more but I guess n54 squished them together. The x values are 1, 2, 3, ?, ?, 6.
Resident Sleepwalker
(Login Syrgot ) _ Re: anyone want to help with this math problem? September 30 2009, 6:47 PM
Sorry Mr. W, my attention span only lasted about 4 minutes.
I'm pretty sure line 3 = 3, 18 though
Lizzlee (Login Lizzlee ) _ Re: anyone want to help with this math problem? September 30 2009, 7:03 PM
Yeah, I came up with
1, 8
2, 14
3, 18
4, 24
5, 28
6, 34
but can't come up with an equation to make it make sense.
Resident Sleepwalker
(Login Syrgot ) _ Re: anyone want to help with this math problem? September 30 2009, 7:30 PM
I came up with that one too but couldn't find an equation.
For the first 4, it's 1x8, 2x7, 3x6 but after that it stops working.
1, 8
2, 14
3, 18
4, 24
5, 28
6, 34
Bider Spite (Login BiderSpite ) Re: anyone want to help with this math problem? September 30 2009, 8:16 PM
I got confused by all the ?????
I was thinking each ? = # "Ta Friggin da"
Amber (no login ) Re: anyone want to help with this math problem? September 30 2009, 8:40 PM
Yeah, Liz, I got that sequence also by just putting equal intervals between all the numbers.
We also came up with the equation y = 6X + 2 and got the values
x y
1 8
2 14
3 18
3and2/3 24
4and1/3 28
6 32
But we wern't sure if the values needed to be equal intervals. Isnt' that just the difference between a linear and non-linear equation?
Funk
(Login Funkenstien ) _ Re: anyone want to help with this math problem? October 1 2009, 11:03 AM
I think you're right with y=6x + 2, which is determined by the first two data points. I think row 6 is right, and for the 4th and 5th row you can't change y but you can solve for x. Because you don't know the x values, you must use your linear relationship to solve for x.
row 4:
24 = 6x + 2
22 = 6x
3 2/3 = x
and so on.
This message has been edited by Funkenstien on Oct 1, 2009 11:32 AM
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