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anyone want to help with this math problem?

September 30 2009 at 6:04 PM
Amber  (no login)

Anyone want to see if you can determine the missing numbers and a rule (equation) for this x/y chart?

x y
1 8
2 14
3 ?????
????? 24
????? 28
6 ?????

 
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Bider Spite
(Login Bider)

Re: anyone want to help with this math problem?

September 30 2009, 6:25 PM 

is it 2,1,4 or 2,14?

 
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Amber
(no login)

Re: anyone want to help with this math problem?

September 30 2009, 6:28 PM 

2, 14. I had them spread out more but I guess n54 squished them together. The x values are 1, 2, 3, ?, ?, 6.

 
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(Login Syrgot)
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Re: anyone want to help with this math problem?

September 30 2009, 6:47 PM 

Sorry Mr. W, my attention span only lasted about 4 minutes.

I'm pretty sure line 3 = 3, 18 though

 
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Lizzlee
(Login Lizzlee)
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Re: anyone want to help with this math problem?

September 30 2009, 7:03 PM 

Yeah, I came up with
1, 8
2, 14
3, 18
4, 24
5, 28
6, 34

but can't come up with an equation to make it make sense.

 
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(Login Syrgot)
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Re: anyone want to help with this math problem?

September 30 2009, 7:30 PM 

I came up with that one too but couldn't find an equation.

For the first 4, it's 1x8, 2x7, 3x6 but after that it stops working.

1, 8
2, 14
3, 18
4, 24
5, 28
6, 34

 
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Bider Spite
(Login BiderSpite)

Re: anyone want to help with this math problem?

September 30 2009, 8:16 PM 

I got confused by all the ?????

I was thinking each ? = #

"Ta Friggin da"




 
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Amber
(no login)

Re: anyone want to help with this math problem?

September 30 2009, 8:40 PM 

Yeah, Liz, I got that sequence also by just putting equal intervals between all the numbers.

We also came up with the equation y = 6X + 2 and got the values

x y
1 8
2 14
3 18
3and2/3 24
4and1/3 28
6 32


But we wern't sure if the values needed to be equal intervals. Isnt' that just the difference between a linear and non-linear equation?

 
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(Login Funkenstien)
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Re: anyone want to help with this math problem?

October 1 2009, 11:03 AM 

I think you're right with y=6x + 2, which is determined by the first two data points. I think row 6 is right, and for the 4th and 5th row you can't change y but you can solve for x. Because you don't know the x values, you must use your linear relationship to solve for x.

row 4:

24 = 6x + 2
22 = 6x
3 2/3 = x


and so on.




    
This message has been edited by Funkenstien on Oct 1, 2009 11:32 AM


 
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