You can't be 1/33 any race. The denominator needs to be a power of two.by qbguy (no login)
No, not even with inbreeding.
No person can be their own ancestor, so the breeding graph is directed and acyclic, so it has an ordering where all of a given person's ancestors come before that person. This ordering permits induction:
For the basis cases, all the 'pure white' and 'pure black' people are 1/20 and 0/20.
The other cases, are children of a p1/2q1 and a p2/2q2 - which comes to (p12q2 + p22q1)/2q1+q2+1, which is of the required form.
|Response Title||Author and Date|
|xkcd||on Feb 21|
|Actually, a person can be his own ancestor.||Solitaire on Feb 28|
|* I think that would be posted in the Incest Forum.............||on Feb 28|
|*Either that or the National Enquirer forum, lol.||on Feb 28|
|*You're wrong... the child becomes a ward of the state. :)||on Feb 28|
|* Tell that to Jesus........||on Feb 28|
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