Looks good, but I can't confirm

The humble mathematical tools at my disposal don't allow me to manipulate such large numbers, but using just 8 significant digits of your solution yields this result: 5.9999999

If your solution is correct, it would be preferable to the published winner since your numbers are over 40 orders of magnitude smaller. I suppose there is comfort in this, even though you are 15 years too late to claim the prize.

Here is the published solution from Pickover's book. I OCR'd the numbers--I didn't trust myself to type them in correctly.

X = 79222057266254960819025292611212161768608793943824566 5806051608621113641830336450448115419524772568639

Y= 677959805103821424723263992665061838773573375138707379 34706199386093375292356829747318557796585767361

Z = 4360668418820711170950024593240851673665433429374 77344818646196279385305441506861017701946929489111120