 Challenge: too many IF  THENsFebruary 18 2011 at 4:45 PM  AlGoreIthm (Login AlGoreIthm)  
 Imagine that the portion of the keyboard that has the numbers 0 through 9 and all 26 letters of the alphabet is divided into 4 quadrants. Quadrant 1 is in the upper left, and moving clockwise towards Quadrant 4.
The following program works fine  it tells you what Quadrant the key pressed belongs in.
But it takes 28 conditionals in the WHILE/WEND loop to do the job of figuring out which Quadrant the key belongs in.
The Challenge: Find the most compact solution to achieve the same user Input and Output.
The fewest conditionals inside the loop wins (nothing).
Note that the program must also include the Upper Case Letters.
The following is the program to be modified, not an entry:
==============================================================================
PRINT " Type any key az (AZ) or 09"
PRINT " ESC to end"
PRINT
WHILE k$ <> CHR$(27)
quadrant% = 0
k$ = INKEY$
IF k$ = "a" OR k$ = "A" THEN quadrant% = 4
IF k$ = "b" OR k$ = "B" THEN quadrant% = 3
IF k$ = "c" OR k$ = "C" THEN quadrant% = 4
IF k$ = "d" OR k$ = "D" THEN quadrant% = 4
IF k$ = "e" OR k$ = "E" THEN quadrant% = 1
IF k$ = "f" OR k$ = "F" THEN quadrant% = 4
IF k$ = "g" OR k$ = "G" THEN quadrant% = 3
IF k$ = "h" OR k$ = "H" THEN quadrant% = 3
IF k$ = "i" OR k$ = "I" THEN quadrant% = 2
IF k$ = "j" OR k$ = "J" THEN quadrant% = 3
IF k$ = "k" OR k$ = "K" THEN quadrant% = 3
IF k$ = "l" OR k$ = "L" THEN quadrant% = 3
IF k$ = "m" OR k$ = "M" THEN quadrant% = 3
IF k$ = "n" OR k$ = "N" THEN quadrant% = 3
IF k$ = "o" OR k$ = "O" THEN quadrant% = 2
IF k$ = "p" OR k$ = "P" THEN quadrant% = 2
IF k$ = "q" OR k$ = "Q" THEN quadrant% = 1
IF k$ = "r" OR k$ = "R" THEN quadrant% = 1
IF k$ = "s" OR k$ = "S" THEN quadrant% = 4
IF k$ = "t" OR k$ = "T" THEN quadrant% = 1
IF k$ = "u" OR k$ = "U" THEN quadrant% = 2
IF k$ = "v" OR k$ = "V" THEN quadrant% = 4
IF k$ = "w" OR k$ = "W" THEN quadrant% = 1
IF k$ = "x" OR k$ = "X" THEN quadrant% = 4
IF k$ = "y" OR k$ = "Y" THEN quadrant% = 2
IF k$ = "z" OR k$ = "Z" THEN quadrant% = 4
IF k$ >= "1" AND k$ <= "5" THEN quadrant% = 1
IF k$ >= "6" AND k$ <= "9" OR k$ = "0" THEN quadrant% = 2
IF quadrant% <> 0 THEN PRINT "Key "; k$; " is in quadrant"; quadrant%
WEND
 
 Responses instr  Michael Calkins on Feb 18, 2011
 scan codes: cmp, adc, sbb  Michael Calkins on Feb 19, 2011
 scan codes: less assembly, more qbasic  Michael Calkins on Feb 19, 2011
 Now the easy way  David on Feb 19, 2011
 My Entry  Anonymous on Feb 19, 2011
 And here's my lengthy version...  Unseen Machine on Mar 6, 2011
 My go at it  ChronoKitsune on Mar 9, 2011


