In centipace-ounce units
G, c, e, Boltzmann k, Avogadro N, and hbar are:
1.00E-9, E9, E-15, E-18, E24, E-30.
All power-of-ten, and all exact save G.

If you were using cp-oz units and for some reason you were forced to switch over to metric then:

Instead of G = 1.00E-9 you would have to use 6.673..E-11.
Instead of c = E9 (a clean billion), use 299792458.
Instead of e = E-15 (a quadrillionth), use 1.602176...E-19.
Instead of k = E-18 (a quintillionth), use 1.38065..E-23.
Instead of N = E24, use 6.02214..E-23.
Instead of hbar = E-30, use 1.0545715..E-34.

That is just a taste--it doesn't stop there. Notice that the metric numbers are not only messier but for the most part also more extreme. You have larger exponents to handle in metric like -34 instead of -30 and -19 instead of -15.

Important constants which are messy and awkwardly large in metric can turn out to be exactly ONE in the modern system. The natural unit of resistance and the natural unit of the Stefan-Boltzmann constant are examples. Both are exactly one in cp-oz; the former is basic to today's standard for measuring electric current and the latter to the fourth-power radiation law---their metric counterparts are messy and unmemorable numbers involving thousands and millionths.

Metric is an antiquated system, when they set the sizes of the units in 1790 they didn't know much about the intrinsic proportions of nature. They got the sizes wrong. It's time to consider modern fully decimal alternatives to that clumsy out-of-date system.
Talent-Mile is one such alternative and here is another: cp-oz.

We should keep in touch with the traditional units of mile (and its relative the pace), ounce, and gallon, because it is turning out that any modern decimal alternative to metric is apt to have these either as base units or as power-of-ten multiples of the base units. They are valuable things to retain the use of.

I'll post this now and append some physics examples as time permits.

****material from previous posts****

The mile, the gallon, and the ounce are power-of-ten multiples of the Planck units of length, volume, and mass.

centipace-ounce units are to Talent-Mile what cgs is to SI. smaller scale. The time unit (trice) is a thousandth of a T-M minute and the rest of the units are defined by stipulating exact power of ten values for these five constants.

c,e,k,Avogadro number, and hbar
E9, E-15, E-18, E24, E-30

Mass unit comes out to be roughly ounce-size, so is called ounce.

We steal the old CGS names dyne and erg for the force and energy units (they've been supplanted officially by "newton" and "joule" so metric doesn't need them).

our erg is 2 millijoules and our power unit [erg/trice] is 36 milliwatts.

Essentially all the good coincidences that make Talent-Mile units pleasant to use carry over to centipace-ounce. The numbers change by a few factors of ten, is all. But I've noticed a few others as well.

The Planck resistance turns out to have value ONE in the cp-oz units. In metric it is some godawful 4108.23...ohms. It is a physically important resistance because it appears exactly in a cold solid-state quantum current gauge that provides the current standard at the national labs.

2pi times that resistance is the basic ratio in the quantum-Hall current gauge which defines the 1990 standard ampere. Nice to have the number be 2pi instead of a messy metric number--exactly 25812.807 ohms by convention in fact (see eg. NIST site)

The density of sunlight in space at this distance from the sun turns out to be 1/100 erg per cubic pace, within a few percent. The average density of our planet turns out to be approximately one. The system has a "centigrade"-like relative temperature scale making freezing equal to zero, though the physics problems mostly use the absolute scale.

Here is a nearby set of T-M examples adapted to cp-oz:

The Prime Directive

Kirk had beamed to the surface of a planet resembling Sun Valley, Idaho in order to accomplish the Prime Directive and check out the local babes. As they strolled past a sheer rock wall, he and Spock noticed a Klingon engaged in bungee-jumping. Spock noticed that simply by hanging at rest in his harness the Klingon had caused the cord to stretch by 7 paces. "Fascinating, Captain," declared the Vulcan half-breed, "We can predict his oscillation period at jump-time."

Ans: The Klingon dangles 7 paces, 700 cp. To find his mass over the spring constant, one divides by g = 1.76 cp/sq.trice. This gives m/k = 400 sq.trice, of which the sqrt is 20 trice. One full bounce takes 2pi times that.



Singapore red light district

Kirk has beamed down to Singapore because one of the houses there is famous all over the universe. While visiting the house on previous occasions, Mozart's librettist Lorenzo Da Ponte invented an anti-gravity machine and installed it in one of the rooms, where the machine eliminates the effect of the earth's gravity.

On entering this room, Kirk and Spock discover everyone floating upwards or bounding slowly off the ceiling as if in a gentle upwards gravity. They are expiencing the centrifugal effect of the earth's rotation. What is the acceleration due to this false gravity?

Ans: The data is best recalled in miles and minutes. The Earth's 3940 mile radius and 1600 minute day---254 minutes to turn a radian---become 3940E5 cp radius and angular period 254E3 trice.
So the centrifugal effect is 394E6/254E3^2 = 0.006 cp per sq.trice.

Note: Since felt gravity is 1.76, that which would be experienced without the effect of rotation is 1.766 cp/sq.trice---just adding on the 0.006.


Spock computes the mass of the earth.

Kirk is visiting a famous house of entertainment in Singapore. Spock is waiting for him in a charmingly decorated parlor and, to pass the time, decides to calculate the mass of the Earth.

Ans: Spock knows that equatorial radius is 3940 miles, which is 3940E5 cp, and that equatorial gravity without the centrifugal effect is 1.766 cp per sq.trice. The universal gravitational constant G has the value E-9 in cp-oz units.

Spock squares the radius, multiplies by 1.766, and divides by G to get the mass of the earth in ounces.

3940E5^2 x 1.766 x E9 = 2.74E26 oz.

*****



The wheel rising into the air

Lawrence of Arabia is riding his camel rapidily across the desert. At the moment he is being pursued by Turks who are angry that Lawrence has placed a charge of dynamite in a culvert beneath the tracks and damaged their locomotive.

With nothing to do except evade the Turks, Lawrence recalls the beautiful sight of a wheel from the locomotive sailing 10 paces up into the blue desert sky and idly wonders the speed with which it emerged from the explosion.

Ans: Twice the height is 2000 cp. The speed is the sqrt of what is obtained by multiplying this by the local acceleration of gravity. Sqrt of 1.76 x 2000 is 59 cp/t. (One centipace per trice is approximately 2/3 conventional mile per hour. So 60 cp/t is about 40 mph.)

********

A farm in Africa 1910

The Baroness Blixen (who wrote under the name Isak Dinesen) had a farm at the foot of the Ngong Hills, a hundred miles south of the Equator in Kenya.

In September at the time of the coffee harvest, the Baroness and her friend Denys Finch-Hatton used to watch the sun set.

Finch-Hatton had a suede antelope-skin vest with a watch pocket in which reposed a brass pocketwatch telling time in trice. On that occasion he observed that the sun took 2370 trice (2.37 Planck minutes) to set from the first moment it touched the horizon till the last sliver of orange disk disappeared.

How far are we from the sun, measured in solar radii?

Ans: Finch-Hatton happened to know that the earth takes 255 minutes to turn a radian relative to the sun. So he reasoned that our distance from the sun is 255/2.37 solar diameters, or 215 times the sun's radius.

[In this case it seems pointless not to work in Planck minutes of 1000 trice each.]

That night the Baroness dreamed that she stood on a surface shining 215^2 brighter than the ground ever gets in Kenya, even with the sun directly over head. In her dream she knew that she was standing on the sun.

One time the beautiful Princess Leia was skimming low over a the surface of a small planet at the familiar highway speed of a mile a minute, except she was in orbit.

Since we are working in cp-oz units her speed was 100 cp/t. (A centipace per trice is about 2/3 conventional mph.)

She had just made a complete circuit which took 125 and 2/3 minutes when giant rats reached up and caught her in an industrial-size butterfly net.

The rats took the Princess to their king, a handsome and well-endowed rat who was bigger and more evil-minded than the rest. The Rat King had Leia spread-eagled in his royal bed chamber and informed her that unless she immediately told him the mass of the planet she would be gang-raped by himself and his minions.

The Princess reflected that 125 and 2/3 minutes divided by 2 pi is 20 minutes. She then curled her lip defiantly and told him that the planet's mass was 20 quintillion ounces (that is 20E3 x E6 x E9).

"We do not use ounces here," said the Rat King with a hideous smile, "our unit of mass is the price in silver of a Life; 30 shekels to be exact."

"Despicable Rat," declared Leia scornfully, "according to Talmud weights, the shekel is 1/1500 of a talent, so that the 30 coins of silver you mention amount to but a mere 20 ounces. Your planet's mass is a quintillion (E18) times the price in silver paid to the Betrayer."

"Curses," said the Rat King, and had his prisoner released and put safely back aboard her ship.

*********
The mass of a planet equals the cube of the speed of any circular orbit times its angular period, divided by G. Leia's speed (E2) cubed was E6 and the angular period was 20E3. G is E-9----so 20E3 x E6 x E9.

An ounce happens to be about 1/1000 of a classical talent mass, which in the Talmudic system was divided into 1500 shekels, so that a shekel is 2/3 ounce. Don't worry we are not going to use shekels in cp-oz, as a rule---except for the Rat King.

The Hindenburg airship was 150 paces long with an effective diameter (as far as hydrogen capacity is concerned) of 20 paces.
The hydrogen volume was 47,000 cubic paces.

As for conditions in Lakehurst NJ in May, one can assume normal sealevel pressure of 219 dyne/sq.cp. and normal body temperature of 2.19 grade. Whenever this factor of 100 pertains, a cubic pace of ideal gas contains E26 molecules.

How much energy is released by combustion of a cubic pace of hydrogen gas at those conditions?

WE NEED A NAME FOR THE VOLTAGE UNIT erg/quad, which is equivalent to 12-some conventional volts. I am going to try ZWOLF, abbreviated Z.

An electronzwolf is about 12 electronvolts---12 so-called "eevee". The macroscopic charge unit is quad and equals E15 (one quadrillion) electron charges.
So the macroscopic energy unit erg equals E15 eezee.

"By oxygens we count the heat
Released from stuff we burn or eat.
Each Oh-Two molecule sets free
Another Third of an eeZee."

This is just how it is. Two H2 molecules burning use one O2 and release one third of an eeZee of energy.
The same arithmetic works for sugar, fat, gasoline, propane, natural gas, spaghetti-and-meatballs, whatever, to a good approximation.

So in the Hindenburg Disaster how much energy was released by burning a cubic pace of hydrogen?

Ans. E26 hydrogen molecules therefore 5E25 oxygen molecules therefore 1.66E25 eeZee therefore 1.66E10 erg.

*********the gas law*******

Avogadro N is E24 items per mole, and Boltzmann k is E-18 erg/grade. So the constant R = Nk of the gas law is:

R = E6 erg per grade-mole.

PV = nRT

but P is 219 and T is 2.19. So how many moles does a cubic pace (E6 cubic cp) contain? 219E6 = n2.19E6
n has to be 100 moles---just another way of saying E26 molecules.

*****recap of cp-oz units*****

In centipace-ounce units
G, c, e, Boltzmann k, Avogadro N, and hbar are:
1.00E-9, E9, E-15, E-18, E24, E-30.
All power-of-ten, and all exact save G.

If you were using cp-oz units and for some reason you were forced to switch over to metric then:

Instead of G = 1.00E-9 you would have to use 6.673..E-11.
Instead of c = E9 (a clean billion), use 299792458.
Instead of e = E-15 (a quadrillionth), use 1.602176...E-19.
Instead of k = E-18 (a quintillionth), use 1.38065..E-23.
Instead of N = E24, use 6.02214..E-23.
Instead of hbar = E-30, use 1.0545715..E-34.

The time unit (trice) is defined as 54 milliseconds and the rest of the units are defined by stipulating exact power of ten values for these five constants.

c,e,k,Avogadro N, and hbar
E9, E-15, E-18, E24, E-30

Mass unit comes out to be roughly ounce-size, so is called ounce.

Length unit comes out roughly 1.6 cm and is called centipace.

Charge unit comes out to be a quadrillion (E15) times the electron charge and is called quad.

Absolute temperature step comes out 141.45 kelvin and is called grade. A relative "centigrade" scale can be constructed with freezing equal to zero---it this then sort of like the old Reaumur scale once used on the European continent. But this is not a big concern right now because all the physics applications need an absolute scale.

We steal the old CGS names dyne and erg for the force and energy units (they've been supplanted officially by "newton" and "joule" so metric doesn't need them).
Our erg is 2 millijoules and our power unit [erg/trice] is 36 milliwatts.

The mile, the gallon, and the ounce are approximate power-of-ten multiples of the natural Planck units of length, volume, and mass. They appear in this system either as base units (ounce) or as power-of-ten multiples of base units. Mile is E5 cp. Gallon is 1000 cubic cp. One is apt to find mile,gallon,ounce in pretty much any modern alternative to metric as long as its conversion factors are power-of-ten.