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Length-Time systems (to make c & g nice)

April 29 2003 at 5:42 AM
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Bryan Parry 

 
I have been trying to create new systems where the relationship twixt massunit-force (as it were) and force is smaller (like 6, 8, 10 or 12).
I have also been trying to make these inch pound.
AND I have been trying to create a good value for c and g. Here is what I have:


1. Time Unit = 1/288,000 days/0.3secs
C = 3.6billion inches per time unit
G = 117.76127in/t/t, 9.813439ft/t/t

2. Time unit = 1/1,000,000 days (0.0864secs)
C = 1 billion inches per time unit
G = 32. 71146in/t/t
Note: you could adjust this slightly to, say, 1.02billion ins for c. Mainly here I was thinking about the barleycorn unit (used in sho9e sizes- 1/3”) and here g = 100brly/t/t nearas damnit.

3. A FUDGE: Time unit = 1/3.217405secs
C = 6.114billion inches per time unit
G = 120in/t/t

4. 1/9.836secs
c = 12billion inches

Out of these, I favour no.1, bnut am curious as to your respective thoughts.

Ps. I’be been thinking about inch-pound-trice again (now that I have a better understanding of c & g)

 
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Bryan Parry

Re: Length-Time systems (to make c & g nice)

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April 29 2003, 5:49 AM 

I have been trying to create new systems where the relationship twixt massunit-force (as it were) and force is smaller (like 6, 8, 10 or 12).
I have also been trying to make these inch pound.
AND I have been trying to create a good value for c and g. Here is what I have:


1. Time Unit = 1/288,000 days/0.3secs
C = 3.6billion inches per time unit
G = 117.76127in/t/t, 9.813439ft/t/t

2. Time unit = 1/1,000,000 days (0.0864secs)
C = 1 billion inches per time unit
G = 32. 71146in/t/t
Note: you could adjust this slightly to, say, 1.02billion ins for c. Mainly here I was thinking about the barleycorn unit (used in sho9e sizes- 1/3”) and here g = 100brly/t/t nearas damnit.

3. A FUDGE: Time unit = 1/3.217405secs
C = 6.114billion inches per time unit
G = 120in/t/t

4. 1/9.836secs
c = 12billion inches

Out of these, I favour no.1, bnut am curious as to your respective thoughts.

Ps. I’be been thinking about inch-pound-trice again (now that I have a better understanding of c & g)

 
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Bryan Parry

Re: Length-Time systems (to make c & g nice)

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April 29 2003, 6:00 AM 

btw, I have name the acceleration unit "accel" and its abbrev is "ac"

 
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Bryan Parry

Re: Length-Time systems (to make c & g nice)

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April 30 2003, 8:51 AM 

Sorry, completely cocked up my calculations, but that was not the point- I think IPT is worth running with #(and I shall)

 
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Leonard

Re: Length-Time systems (to make c & g nice)

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May 2 2003, 6:40 PM 

Hello Bryan,
I have been away from this board for a few days and
just looked in. I was delighted to see several
posts from you. Maybe we can stir up some interest.

I will look over your proposed system(s) and
let you know my reaction. This seems like a good
place to sketch out, and try sample calculations with, system that make natural constants (such as c and g)
take on convenient values.

 
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Leonard

an idea along those lines

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May 2 2003, 7:40 PM 

I see that you want to try adjusting the time unit so as to make g nice, and also to reinforce some traditional units.

I will throw out an idea to see if it is helpful, if not ignore it.

The old germanic weight "mark" has most commonly been half a local pound. Whatever the pound or pfund was (before metric) the mark or marca or marc or whatever was most often half. They even had marks in French and Spanish, it was a widespread weight.

Let us see if we can have a system where there is a mark of force, and a pound of mass.
And where in some specified version of standard sealevel gravity it will turn out that the pound of mass, if you weigh it in that standard gravity, will have a weight-force of exactly two marks.

Is this appealing or not? Well we have to try it out to see.

I think that system would result from defining a time unit of a *quarter second*. For no particular reason let us call a quarter second a "quid".

Then acceleration of gravity might be standardized at 2 feet per quid per quid.

I know it is 32 feet per second per second but since a quid is only a quarter as long, gravity will be 2 instead of 32.

So if pound is unit mass, the pound will weigh 2 force units. The number of force units which the unit mass weighs is always the number that appears in standard gravity.

So if standard gravity is 2 feet per q per q, then a pound has to weigh 2 "whatever the force unit is".

And we could call the force unit a mark.

Tyres pumped up to 30 pounds per square inch would be
60 marks per square inch. I am leaving this quite vague and presenting it more as a question or as a suggestion of something you might want to consider.


 
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