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Crosman999's Sheridan

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sealing diameter determines area, spring determines force

December 14 2011 at 4:29 PM
  (Login Voltar1)
Crosman Forum Member
from IP address 72.25.192.4


Response to sooooo, all the force needed to overwhelm the spring

so if you apply 5#s force to a 5/16" inlet check the cracking force will be 65 psid

if that force is 20 #s force of course the pressure is 261 psid ( pounds per sq inch differential)

 
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