December 23 2010 at 7:01 AM

In the case of twin A on board of train moving at v relative to platform where twin B stands, when they reunit (disregard acceleration )which will be the case:
1- a & b look the same age
2- A sees B older
3- B sees A older
4- Both A & B see each other older
A brief expl. is also welcome

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Anomalous

December 23 2010, 11:11 AM
 Please answer this Q. December 23 2010 at 7:01 AM sami: (In the case of twin A on board of train moving at v relative to platform where twin B stands, when they reunit [sic] (disregard acceleration )which will be the case:) 1- a & b look the same age 2- A sees B older 3- B sees A older 4- Both A & B see each other older 4- Both A & B see each other older When they reunit[e] time will have passed, therefor, they will both see each other as older because, they will be older.
Sherlock

December 23 2010, 1:45 PM
 Exactly right, Anomalous! Einstein's absurdity , in my very humble opinion, is in making the measurement of "time" an axis in some sort of coordinate system which defies logic. When the image of the hands of a clock, or even the digits of a digital clock, leave the clock in the form of a wave front, neither the hands nor the digits change within the image, as the image travels the distance from the clock to the observer. Both the clock's hands or digits keep changing, as well, so does the observer's clock; indicating a new present moment, sending additional images. Changing the distance between clock and observer merely changes the duration of the time the image spends in transit. The duration of the transit of the image is the entire object and subject of relativity. The rest is conjured out of whole cloth.
Anonymous

January 11 2011, 12:17 PM
 You can't disregard acceleration. While the train is moving, A is aging more slowly relative to B. But if you want them to meet up and compare notes before and after the train ride, you must accept the General Theory as part of the result. Otherwise, you're just going to get silly answers.
Anomalous