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# Max lenth of putt with "pure in line stroke"

May 27 2006 at 3:47 PM

Dear Geoff,

I use your recommendations for both Stroke mechanichs (Pure in line) as well as for tempo (Let the putter -arms-shoulders accelerate only from the force of gravity). I have noticed that with max backstroke, and still only use gravity as accelerating force, my max length is around 65 feet (I use a relatively short putter, 30.5"). I can putt much longer with the pure in line stroke, by adding energy from my shoulders to roll the ball. However I do not want to mix upp my normal stroke with a force driven motion
for these longer putts.

-I Solve this by changing my putting mecanics completely for putts over 65 feet , I use a chipping-like set up and also grip the putter like I grip a wedge for a chipshot.

-Have you given this issue any consideration, and if so what is your thoughts ?

As always, thanks for a fantastic site !

Christer

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24.167.140.53

May 28 2006, 7:28 AM
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sammy
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# Re: Instincts and Adding Force

May 28 2006, 1:57 PM
 Geoff: I hope you don't think I am stalking you on this point, but could you be confusing vertical gravity force with angular momentum through the bottom of the putting stroke? I still think that the reversal at the end of the backstroke to the forward stroke is controlled by a decelerating torque and then an accelerating torque to start the down stroke. The angular momentum created by the initial torque is what is felt as the putter head sweeps through the bottom of the putting stroke ... and not the insignificant vertical gravity force acting through 1.35" or less of drop. A torque is not a force. Given that the initial down stroke breakaway torque results in most of the final momentum through impact, the ball roll distance is determined by how much initial torque is applied and not necessarily how long the back stroke. It's unfortunate that the feeling of angular momentum is confused with gravity as in a free-swinging pendulum. Perhaps the concept should be that of a free-wheeling flywheel even though it's through a very small angular displacement .. ~12º for a 12" back stroke. Impeding the angular momentum through impact is decelerative. Is it not the letting go of the kinetic angular momentum rather than the pendular drop by the gravity force .. ??
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