Dear Sammy,
In trying to understand our communication gap, it strikes me that perhaps the underlying notions of the "drop" and what you describe as "feel" don't agree with my understanding. Let me try to attack the issue that way.
DROP
The "drop" of an object in gravity vertically down over a specific distance will a) take place in one and only one time span determined solely by the distance of the drop, and 2) will reach the end of the span with one and only one peak velocity also determined solely by the distance of the drop.
The "drop" or "swing" in gravity of an object (bob) at the end of a pendulum (rod fixed to a pivot) that starts at a specific height above the bottom of the swing arc (the same height as in the previous vertical-drop example) is not a drop vertically down that height span but is a combination of down and across laterally or translationally beneath the pivot. At the instant of the beginning of the drop, the direction of the object's drop is ALL vertical, but instantaneously is constrained by the pivot and rod so that the vertical dropping is transformed in a smooth manner to more and more horizontal or lateral motion. There is a blend of vertical and horizontal dropping. Starting the bob back 90 degrees off vertical so the rod parallels the ground, the bob starts 100% vertically dropping and instantly after the start of the drop, the bob is dropping (say) 99% vertically and 1% horizontally. The further along the pendular arc the bob drops back towards the bottom of the stroke, the more the bob's drop becomes horizontal and the less the blend is vertical. Right at the bottom of the arc, ALL of the bob's motion is 100% horizontal and there is no further dropping vertically allowed. Then the bob continues upward, reversing the pattern or blend of "up" and "across" with increasing "up" and decreasing "across".
The interesting thing about the HEIGHT of the drop of a pendulum is that the TIME required for the bob to reach the bottom along a lengthy pendular arc is the NOT THE SAME as the time of a vertical drop from tghe same height, but the peak speed at the bottom of the pendular swing is the SAME as the PEAK SPEED after a vertical drop from the same height. The "peak speed" is really horizontal velocity in a pendulum, whereas in a vertical drop the "peak speed" is vertical velocity. Hence, the pendulum transforms the gravitational acceleration of a vertcal drop to the SAME velocity horizontally as the bob would have by dropping vertically.
Let me show that the two calculations are the same peak speed.
Vertical drop: 1.35 inches of vertical drop (H) in gravity (g = 384 inches / second per second acceleration on earth) results in a drop that takes TIME T = SQR(2 x H / g) and that reaches a peak vertical velocity (PVV) at the end of the drop of PVV = T x g. Starting with H = 1.35 inches,
T = SQR(2 x 1.35 / 384) = 0.0834 seconds
and peak velocity at end of 0.0834 seconds of gravtitational acceleration is
PVV = 0.0834 x 384 = 32.2 inches per second vertical velocity.
Pendular swing: 1.35 inches starting height with a rod 54 inches long (L) and a backstroke 12" back from vertical results in a drop that takes TIME T = 2
pi SQR(L / g) = 2 x 3.14 x SQR (54 / 384) = 2.35 seconds from top of backstroke to top of thrustroke and back again to top of backstroke. We're only interested in the time from top of backstroke to bottom of swing arc, which is 1/4th this time, or 0.59 seconds. The pendulum transformation of a 1.35" drop eventuates into a swing of 12"+ along a circular arc that requires a lot more time to traverse, 0.59 seconds, whereas the vertical drop rerquires only 0.083 seconds (12 times longer motion).
The peak horizontal velocity (PHV) of the bob (putterhead) at the bottom of the swing arc starting at maximum angle off vertical of THETA degrees (12.84 degrees to raise putter 1.35") is just the same as the PVV, from the formula
PHV = SQR(2 x g x [Lx(1-cosTHETA)])
PHV = SQR(2 x 384 x 54 x [1 - cos(12.84 degrees)])
PHV = SQR(2 x 384 x 54 x [1 - 0.975])
PHV = SQR(2 x 384 x 54 x 0.025
PHV = SQR(1036.8)
PHV = 32.2 inches per second of horizontal velocity.
That's interesting! For the starting height of 1.35", the pendular swing of a 54-inch length rod has the bob (putter head) moving down and across in a period of time 12 times longer to arrive at the SAME peak velocity as a vertical drop of the same height. All of the potential energy of the height becomes transformed by the pendulum arrangement into horizontal velocity at the bottom of the stroke that is exactly the same velocity as gravity gives a vertical drop from the same height.
The longer the pendulum, the slower the putter head accelerates smoothly along a longer arc from its starting height to the SAME peak velocity it would get in a much shorter and faster vertical drop.
No torquing is required to generate this 32.2 inches per second velocity at the bottom of the pendular swing. Gravity does it all.
FEEL
"Feeling" the difference between a gravity vertical drop and a pendular swing from the same height is not the same, although the forces involved at impact are the same.
In a gravity free-fall vertically of the hand onto the thigh from 1.35" height, the only "feel" is the impact of stationary thigh against underside of hand. If you raise the hand 1.35" and really relax and "drop" it, you feel a "pat" against the thigh. You can see about the same thing by lifting a golf ball one diameter high (1.68" -- not too much higher) and dropping it onto your open palm. Now if you took a 360 gram putter head and lifted it 1.35" off the palm and thenm dropped it, you would "feel" the same energy ("momentum", mass times velocity at impact) that the ball would "feel" in a pendular swing from the same height (i.e., 12" backstroke raising the putter head 1.35" off the ground). This "force" will generate a ball speed off the putter face of 1.56 times the putter head speed at impact, or 50.2 inches per second. On a Stimp 10 green where a ball exits the Stimpmeter at about 70 inches per second to roll 10 feet, the 50.2 inches per second ball will roll about 5/7th of 10 feet, or 7.2 feet (10' * 50/70).
I don't know that a human hand weighs as much as a 360 gram putter head, so the analogy of dropping the hand onto the thigh may not quite be enough force to compare. Dropping a 360 gram putter head onto the palm or thigh, though, would do the trick.
In comparison, the "feel" in a pendular swing is more complex and involves more body parts and areas DURING the down-fall over a much LONGER period of time, and thereafter the "feel" of impact is added to the experience. While it may be true that the v elocity at impact is the same in both cases, and so the momentum or energy transferred into the ball is the same, the "feel" is not the same. Comparing a hand drop onto the thigh just doesn't get the true "feel" of a pendular swing over a greater distance and a longer time.
Your "suspicion" that my pendular length changes during the backstroke to lengthen the pendular rod is just that -- your suspicion. I can only assure you that by teaching a natural full arm hang, no hands, and a stable pivot position during the stroke, that I always pay close attention to NOT allow this sort of change in the shape of my "triangle." There is no "play" left in the system with which I could "extend" the radius of the stroke greater than 54 inches. I teach this explicitly every day, but you don't seem aware of this. The putter NEVER rises less than 1.35" in a 12" backstroke when I do what I teach. I avoid artificially keeping the putter low and just don't raise the hands or stick the arms and hands any lower -- there is no change at all in the triangle shape of my setup during the stroke.
I can only assure you that I know the difference between the feeling of letting an arm drop to my side by gravity alone following lifting and holding the arm out 12" from the side and then RELAXING the muscles that were holding it there from the feeling of TORQUING the arm down to impact against my side. In the same manner of paying attention to the feelings of the body in relaxation versus torquing down with muscles, I am also keenly aware of the difference of the feeling of dipping the whole shoulderframe to position the triangle of shoulders and arms back and under the pivot to position the putter 12" back and then RELAXING the muscles that were holding this triangle at this backstroke position so that the whole triangle drops freely back to level equilibrium, versus the feeling of TORQUING the triangle down at any point in the return to level, specifically including torquing the triangle at the very beginning of the return down.
It may be a subtle difference TO YOU and hence cause you concern and doubt and suspicion about confusing the two feelings, but it is not a subtle difference at all TO ME. It's black and white, night and day, to me. One is a NON-voluntary releasing of the tension of the triangle being HELD stationary at the top of the backstroke, while the other is a voluntary ADDING of tension to torque the triangle down from its stationary holding. Big difference.
Moreover, as Crenshaw experiences it, so do I -- the only toquing is at the beginning of the takeaway, with a ballistic tossing back of the triangle with as much smoothness as the situation allows. ("Once I start the putter back, it feels as if the stroke completes itself.") After this initial toss back, the triangle coasts upward and backward under the retarding influence of gravity (ONLY) until the putter head reaches a transitional pause at the top of the backstroke (like a tennis ball toss for the serve). Then the triangle starts down under the influence of gravity (ONLY) and gathers velocity over around a half second swinging back to the bottom. This simple one-toss-is-all-the-voluntary effort stroke will send a ball 7.2 feet across a Stimp 10 green, with my putter. Every time.
Now let me focus more closely on one specific sort of "feel" -- the putter handle in the hands. In a free-fall pendular swing, the hands and the handle inside the hands are moving in the same direction and under the same acceleration, just like (handle) riding in a car (hands of grip form). Acceleration down, however, is not the same as acceleration horizontally across a gravitational field. Since there is SOME CHANGING BLEND of accleration down and across in a pendular swinging down and under and across, there ought to be a CHANGING BLEND of acceleration down and acceleration across. The lower the putter head swings towards the bottom, the MORE the accleration is horizontal and the less it is vertical. This matters to what the hands "feel". The hands do not feel anything at all in a free-fall vertical drop of hands and handle together. But as the hands and handle start to gain horizontal acceleration, do the hands feel the handle "pressed back into the seat"? The answer from physics is: "No, not if both the handle and the hands are undergoing the SAME FORCES bringing about the acceleration of both at the same rate. And they are. The only FORCE in this sort of swing is gravity, acting jointly the same on the hands and the handle inside the hands.
But when there is torque bringing the putter down with force of the arms-hands, then there are forces in addition to gravity, and the force of the hands acting of the handle "presses the handle back into the seat of the hands" as an acceleration of a car down a horizontal road will press the occupant back into the seat. Here, the hands' tactile receptors will "feel" the handle's pressure more against the back side of the grip of the two hands and less on the front side of the hands. That's the feeling of "shoving" the putter handle along the swing arc. (You could also feel a "pulling" of the handle along the arc by the lead hand and arm.)
When a golfer does not torque the putter handle down, he instead "rides" the handle with his hands and with his turning shoulder frame. Riding the putter down may or may not require the golfer to move the shoulder frame so as to "keep up" with the handle as it swings freely down. But if the golfer has to "move" the shoulder frame to preserve or maintain the sensation of "nothing changing" inside the hands, then he may think of this as a feeling associated with torque, but it is not, since he is in fact not imparting a torque to the putter by simply keeping up with the handle to "ride it down."
If you do NOT feel this extra pressure of the handle against the rear palm, you are ipso facto not torquing the putter. That's exactly what I teach and experience -- to ride the putter down and experience "no change" inside the hands coming down to the bottom. It's not physically possible to torque the putter down with arms and hands and still experience "no change" coming down. Since I always attend very carefully to whether I feel anything in the hands coming down, and I don't, then I COULD NOT BE TORQUING the putter in the downstroke.
Your suggestion that human tactile sensitivity is not sufficiently accute to detect these sorts of "feelings" does not take into account data from modern psychophysics of human perception. Human fingers, palms, tongues, and lips are the most sensitive areas of the skin. Human skin can detect a deformation of the skin of as little as 0.001 mm or 0.00004 inches, and the human fingers of male adults can detect two points of pressure as separate even though separated by as little as 3-4 mm, compared to forearm sensitivity of about 10 mm and shoulder sensitivity of 40-45 mm.
When the putter is moved by torque forces of the hands and arms, the inertial properties of the putter itself generate "stress", "strain" and "shear" deformation by pressure of the handle against the skin of the palm and fingers and fingertips. When the putter is deliberately stopped at the top of the backstroke, as opposed to allowing the putter and hands jointly to coast to a stop under the gradual slowing of grtavity only, the putter handle tends from inertia to go past the stopping point, and this forces the side of the handle against the lead-side palm with greater pressure, and also places a shearing pressure between the flat of the putter handle surface on the top and the thumbs tips. Any golfer can detect these changes in "feel" if he chooses to attend to them.
The more the golfer sets his ideal as "feeling nothing change" at these transitions and during the downstroke, the more his motion pattern has the hands and putter undergoing the SAME gravitational forces only, as there is no added force of torque from the body moving the putter outside / faster than this pattern. The "feel" of "nothing changing" is a lot clearer kineasthetic cue to the tempo of the stroke than any effort by the golfer to gen erate a specific level of pressure of the handle against the rear palm in the downstroke.
You should pay more attention to the consequential feel in the hands of torquing the putter down to see what I'm talking about.
In addition, since I also teach that the putter head ALWAYS arrives at the bottom in the same timing that a free pendulum would arrive, and since I attend very carefully all the time to whether this is so, and it is so, then I must not be accelerating the putter any faster than gravity accelerates it. Again, it is not possible to preserve this timing and also be torquing the putter down. The only question is whether my putter arrives sooner than a pendulum downfall would have it arrive. It doesn't.
I also teach that timing matters, but "feel" does not. To illustrate this, I use what I call a "Quasimodo Stroke." This stroke is made with great tension and malformation of body posture, but nonetheless adheres to the timing of an instinctive, gravity-sponsored stroke ("one potato" back and "... two" to impact). So long as Quasimodo adheres to the timing, his "feel" is utterly irrelevant to distance control. The only variable that matters is putter head velocity at impact, and the backstroke size plus the timing guarantees that this will result correctly despite weird "feel" in the body. Counterintuitive perhaps, but nonetheless true. If you use "normal" grip and postures, you simply cannot "torque" the stroke down and still match up the movement timing to a gravity-sponsored stroke. If the timing is what the timing in a gravity-sponsored stroke should be, then ipso facto you COULD NOT HAVE TORQUED the stroke down.
You should learn the timing of the pendulum downfall and then pay attention to the downstroke timing of your putting stroke. It's simple: if you're early, you are torquing. If you're on time, you're not.
The "feel" of this sort of stroke is a blast-off toss or shove back and then nothing at all but the feel of the triangle freely swinging in gravity as it will, back and then down.
Just toss your arms back and up from your sides and DO NOTHING except wait for them to flop back to your thighs. Try to make the toss back last "one potato" to the point of directional transition at the top of the "backstroke." You should start to notice the difference in feel of the dropping without torquing and the feel of "bringing" the arms back against the sides with torque.
Cheers!
Geoff Mangum
Putting Coach and Theorist
PuttingZone
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