more infoby (no login)I'm after the angle of an oblique angled triangle. I know all sided but no angles. cos a = (b^2+c^2-a^2)/2bc thus a= arc cos (b^2+c^2-a^2)/2bc ) I think |
| Response Title | Author and Date |
| Don't forget there's no arccos in QB | David on Jul 22 |
| Sorry, disregard what I said. | on Jul 22 |
| Better arccos | Zom-B on Jul 23 |
| Even better... | on Jul 23 |
| That's not better. ππππππππ | Ben on Jul 23 |
| * Then ya gotta SHARE π! I DON'T SHARE π π π π! | on Jul 23 |
| *LOL, keep the new forum handle | on Jul 23 |
| *Why not just 2 * ATN(1)? | on Jul 23 |
| *Didn't see that, you're right | Ben on Jul 23 |
| * Does that make it any better kid? Will DOSBOX run it? :-P | on Jul 24 |
| Thanks Everyone | nik on Jul 27 |